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Require `return` in all match branches 

Before the parser only checked if the catch-all branch has a return in
order to determine if the entire match block has a return.

This code block was assumed to always return.

    match value:
        "test":
            print("test")
        _:
            return

Now as soon as one of the branches has no return, the entire match block
is marked to not have a return.
3.2
Daniel Spaniol 2019-02-20 20:49:48 +07:00
parent 132e2f458d
commit 79176decd5
1 changed files with 4 additions and 2 deletions
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6
modules/gdscript/gdscript_parser.cpp
Unescape Escape View File

@ -2211,6 +2211,8 @@ GDScriptParser::PatternNode *GDScriptParser::_parse_pattern(bool p_static) {
void GDScriptParser::_parse_pattern_block(BlockNode *p_block, Vector<PatternBranchNode *> &p_branches, bool p_static) {
int indent_level = tab_level.back()->get();
p_block->has_return = true;
while (true) {
while (tokenizer->get_token() == GDScriptTokenizer::TK_NEWLINE && _parse_newline())
@ -2268,8 +2270,8 @@ void GDScriptParser::_parse_pattern_block(BlockNode *p_block, Vector<PatternBran
current_block = p_block;
if (catch_all && branch->body->has_return) {
p_block->has_return = true;
if (!branch->body->has_return) {
p_block->has_return = false;
}
p_branches.push_back(branch);